When we refer to number less than one in this section, we mean in the range 0<n<1, not negative values.
Objective:
To find squares and square roots of numbers outside the normal range.
General:
- Finding squares and square roots of numbers less than 1 and greater than 100 is done using the exact same process of the slide rule. However, we will need to rewrite the number in an appropriate first.
Method for Squares:
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Write the number in scientific notation.
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Determine the square of the decimal part as normal.
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Multiply the exponent of the power of ten by two.
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Multiply the result from the rule by the new power of ten.
Method for Square Roots:
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Write the number so that a power of ten divisible by 2 is the factored out without the decimal part not going less than 1.
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Determine the square root as normal.
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Divide the index of the power of ten by two.
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Multiply the result from the rule by the new power of ten.
Example 1: Calculate 1142
Writing 114 in scientific notation gives 1.14 x 102. Now find 1.142 as usual.
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Move the cursor to D1.14
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Read the result A1.3
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Multiply the exponent by 2 giving 4.
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Multiply the result by 104
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Answer: 1.3 x 104 = 13000
Example 2: Calculate 47502
Write 4750 in scientific notation giving 4.75 x 103. Now find 4.752 as usual.
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Move the cursor to D4.75
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Read the result A22.5
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Multiply the exponent by 2 giving 6.
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Multiply the result by 106
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Answer 22.5 x 106 = 22,500,000
Example 3: Calculate 0.002552
Write 0.00255 in scientific notation giving 2.55 x 10 -3. Now find 2.552 as usual.
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Move the cursor to D2.55
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Read the result A6.5
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Multiply the exponent by 2 giving -6.
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Multiply the result by 10-6
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Answer 6.5 x 10-6,/ = 0.0000065
Example 4: Calculate √235.
The power of ten with exponent divisible by 2 that can be factored out is 102, so we rewrite 235 as 2.35 x 102.
Example 5: Calculate √455000.
The power of ten with exponent divisible by 2 that can be factored out is 104, so we rewrite 455000 as 45.5 x 104. Now find √45.5 as normal.
Example 6: Calculate √0.000039.
The power of ten with exponent divisible by 2 that can be factored out is 10-6, so we rewrite 0.000039 as 39 x 10-6. Now find √39 as normal.
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Divide the exponent by 2 giving -3.
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Multiply the result by 10-3.
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Answer: 6.25 x 10-3 = 0.00625
Practice Questions: Evaluate the following:
- 2252 (Ans: 50600)
- 4602 (Ans: 212000)
- 0.00552 (Ans: 0.0000303)
- √890 (Ans: 29.8)
- √63,500 (Ans: 252)
- √0.0000635 (Ans: 0.00797)